int lcs(int i, int j, int count) { if (i == 0 || j == 0) return count; if (X[i-1] == Y[j-1]) { count = lcs(i - 1, j - 1, count + 1); } count = max(count, max(lcs( i, j - 1, 0), lcs( i - 1, j, 0))); return count; }
For example:The X contains AABB and Y contains AACB i want my recurrence relation to skip c to give AAB as the lCCS, this is what i have done so far.