Set the default GCC to Xcode Command Line Tools

How can I ensure that gcc points to a particular compiler? Can I make a permanent symbolic link to the xcode version of gcc?

I have several versions of the gcc compiler installed on my system, including

`gcc-11` found at `/usr/local/gcc-10/share` (compiled from source following these [instructions][1])`gcc-9.3.0` found at `/usr/local/Cellar/gcc/9.3.0_1/share``gcc-4.8.5` found at `/Users/PatrickT/miniconda/pkgs/gcc-4.8.5-8/share`

The default version is gcc-4:

gcc --versiongcc (GCC) 4.8.5which gcc/Users/PatrickT/miniconda/bin/gcc

This miniconda version of gcc is not working for me. If I remove miniconda from the PATH, my system reverts to another version of gcc and everything works as expected. However, I do use miniconda's Python and would therefore like to keep it on my PATH. In my .zhrc profile (apparently, MacOS Catalina has moved the .bashrc to .zhrc), I have:

export PATH="/Users/PatrickT/miniconda/bin:$PATH"export PATH="/usr/local/bin:$PATH"export PATH="/usr/local/Cellar/gcc:$PATH"export PATH="/usr/local/gcc-10/bin:$PATH"

I have tried to change the order of these lines, but it has made no difference: miniconda's gcc remains the default compiler, unless I remove the first line completely, but then... I'm unable to use conda's Python!

Background: I'm not using the gcc directly, but I appear to need it to compile certain scripts. I have both the xcode command line tools and the xcode application, if that matters. I'm on MacOS Catalina 10.15.4.