Gcc vs clang difference in qualified class member lookup within template

The following code produces different results when compiled using gcc 14.2 or clang 19.1:

namespace mylib {    template <typename Type> void Function(const Type& t) {        // Note: explicit Type:: qualification        t.Type::Foo();    }}class Type {    public:        void Foo() const {            std::cout << "Base function";        }};class DerivedType: public Type {    public:        void Foo() const {            std::cout << "Derived function";        }};int main() {    mylib::Function(DerivedType{});}

• in gcc 14.2: DerivedType::Foo() is called.
• in clang 19.1: Type::Foo() is called.

Any idea which behavior should be considered correct, if any?

Note: the two compilers produce the same output if class Type is renamed to something different from the Function template argument, in which case DerivedType::Foo is called also by clang.