Why is the first argument of getline a pointer to pointer "char**" instead of "char*"?

I use getline function to read a line from STDIN.

The prototype of getline is:

ssize_t getline(char **lineptr, size_t *n, FILE *stream);

I use this as a test program which get from http://www.crasseux.com/books/ctutorial/getline.html#getline

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int atgc, char *argv[])
{
    int bytes_read = 1;
    int nbytes = 10;
    char *my_string;

    my_string = (char *)malloc(nbytes+1);

    puts("Please enter a line of text");

    bytes_read = getline(&my_string, &nbytes, stdin);

    if (bytes_read == -1)
    {
        puts ("ERROR!");
    }
    else
    {
        puts ("You typed:");
        puts (my_string);
    }

    return 0;
}

This works fine.

My doubts are?

1. Why use char **lineptr instead char *lineptr as a parameter of function getline?

2. Why it is wrong when I use the following code:

   char **my_string;
   bytes_read = getline(my_string, &nbytes, stdin); 
   

3. I am confused with * and &.

Here is part of warnings:

testGetline.c: In function ‘main’: 
testGetline.c:34: warning: pointer targets in passing argument 2 of  
  ‘getline’ differ in signedness 
/usr/include/stdio.h:671: 
  note: expected ‘size_t * __restrict__’ but argument is of type ‘int *’  
testGetline.c:40: warning: passing argument 1 of ‘putchar’ makes integer 
  from pointer without a cast 
/usr/include/stdio.h:582: note: expected ‘int’ but argument is of 
  type ‘char *’

I use GCC version 4.4.5 (Ubuntu/Linaro 4.4.4-14ubuntu5).