Copy a byte to another register in GNU C inline asm, where the compiler chooses registers for both operands

I'm trying to mess around with strings in inline asm for c. I was able to understand how strcpy works (shown below):

static inline char *strcpy(char *dest, char *src)
{
  int d0, d1, d2;
  char temp;

  asm volatile(
    "loop:  lodsb;"   /* load value pointed to by %si into %al, increment %si */
    "       stosb;"   /* move %al to address pointed to by %di, increment %di */
    "       testb %%al, %%al;""       jne loop;"
    : "=&S" (d0), "=&D" (d1), "=&a" (d2)
    : "0" (src), "1" (dest)
    : "memory"
  );
}

I'm trying to use this structure to make it so I can modify individual characters of the string before returning them. As a result I'm attempting something that looks like:

static inline char *strcpy(char *dest, char *src)
{
  int d0, d1, d2;
  char temp;

  asm volatile(
    "loop:  lodsb;"   /* load value pointed to by %si into %al, increment %si */
    "       mov %2, %3;" /* move al into temp */
    /*
     *
     * Do and comparisons and jumps based off how I want to change the characters
     *
     */
    "       stosb;"   /* move %al to address pointed to by %di, increment %di */
    "       testb %%al, %%al;""       jne loop;"
    : "=&S" (d0), "=&D" (d1), "=&a" (d2), "+r" (temp)
    : "0" (src), "1" (dest)
    : "memory"
  );
}

Where I'm basically moving the byte put into %al by the lodsb instruction into a temp variable where I do any processing after. However, it seems that the character is never actually stored in temp for some reason I cannot figure out.